A) react with alcoholic potash and give the same product
B) are position isomers
C) contain the same percentage of chlorine
D) are both hydro lysed to the same product
Correct Answer: D
Solution :
[a] \[\underset{C{{H}_{2}}Cl}{\overset{C{{H}_{2}}Cl}{\mathop{|}}}\,\xrightarrow[alcohol]{KOH}\underset{CH}{\overset{CH}{\mathop{|||}}}\,;\]\[\underset{CH}{\overset{C{{H}_{3}}Cl}{\mathop{|}}}\,\xrightarrow[alcohol]{KOH}\underset{CH}{\overset{CH}{\mathop{|||}}}\,;\] hence true [b] Both are position isomers [c] Since, they are isomers, percentage of C, H and Cl in both will be same. [d] \[\underset{C{{H}_{2}}Cl}{\overset{C{{H}_{2}}Cl}{\mathop{|}}}\,\xrightarrow[{}]{hydrolysix}\underset{CHOH;}{\overset{C{{H}_{2}}OH}{\mathop{|}}}\,\] \[\underset{CHC{{l}_{2}}}{\overset{C{{H}_{3}}}{\mathop{|}}}\,\xrightarrow[{}]{hydrolysix}\underset{CH{{(OH)}_{2}}}{\overset{C{{H}_{3}}}{\mathop{|}}}\,\xrightarrow[{}]{-{{H}_{2}}O}\underset{CHO}{\overset{C{{H}_{3}}}{\mathop{|}}}\,\] Hence, statement [d] is wrong.
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