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JEE Main & Advanced Sample Paper JEE Main Sample Paper-39

  • question_answer
    An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 mL. The volume of 0.1 N NaOH required to completely neutralize 10 mL of this solution is:

    A)  40 mL                        

    B)  20 mL

    C)  10 mL                        

    D)  4 mL

    Correct Answer: A

    Solution :

     Normality of oxalic acid \[=\frac{6.3\times 1000}{63\times 250}=0.4;\] \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[{{V}_{1}}\times 0.1=10\times 0.4\] \[\therefore \] \[{{V}_{1}}=40mL\]


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