JEE Main & Advanced Sample Paper JEE Main Sample Paper-39

  • question_answer
    By what ratio the average velocity of the molecule in gas changes when the temperature is raised from 50 to \[200{}^\circ C\]?

    A)  \[\frac{1.21}{1}\]                  

    B)  \[\frac{1.46}{1}\]    

    C)  \[\frac{2}{1}\]                       

    D)  \[\frac{4}{1}\]

    Correct Answer: A

    Solution :

     According to the kinetic theory of gases, the average velocity of the molecules in the gas is given by the expression \[v=\sqrt{\frac{8RT}{\pi M}}\]where T is the absolute temperature and R is the gas constant. Thus the average velocity can be taken as proportional to the square root of the absolute temperature. Hence the ratio of the average velocity at \[200{}^\circ C\] to that at \[50{}^\circ C\] will be equal to \[\sqrt{\frac{273+200}{273+50}}\]which is 


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