A) \[1.5\times {{10}^{10}}J\]
B) \[28.8\times {{10}^{-10}}J\]
C) \[6\times {{10}^{-10}}J\]
D) \[9\times {{10}^{-10}}J\]
Correct Answer: B
Solution :
\[E=m{{c}^{2}}=(2\times 1.6\times {{10}^{-27}})\times {{(3\times {{10}^{8}})}^{2}}\] \[=28.8\times {{10}^{-27}}\times {{10}^{16}}J=28.8\times {{10}^{-11}}J\] \[=28.8\times {{10}^{-10}}J\]
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