A) \[sp<s{{p}^{2}}<s{{p}^{3}}\]
B) \[sp<s{{p}^{3}}<s{{p}^{2}}\]
C) \[s{{p}^{3}}<s{{p}^{2}}<sp\]
D) \[s{{p}^{2}}<sp<s{{p}^{3}}\]
Correct Answer: C
Solution :
More the s-character, more is the stability of the carbanion. hence the correct order is sp > sp2 > sp3.You need to login to perform this action.
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