A) A
B) B
C) C
D) D
Correct Answer: B
Solution :
In the charged metallic sphere potential is given by \[V=\left\{ \begin{matrix} \frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{R}\text{where}\,r\le R \\ \frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{R}\text{where}\,r>R \\ \end{matrix} \right.\] So graph isYou need to login to perform this action.
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