A) 40 mL
B) 20 mL
C) 10 mL
D) 4 mL
Correct Answer: A
Solution :
Normality of oxalic acid \[=\frac{6.3\times 1000}{63\times 250}=0.4;\] \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[{{V}_{1}}\times 0.1=10\times 0.4\] \[\therefore \] \[{{V}_{1}}=40mL\]You need to login to perform this action.
You will be redirected in
3 sec