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JEE Main & Advanced Sample Paper JEE Main Sample Paper-39

  • question_answer
    A metal M reacts with \[{{N}_{2}}\] to give a compound 'A' (M3N). 'A' on heating at high temperature gives back 'M' and 'A' on reacting with\[{{H}_{2}}O\]gives a gas 'B'. 'B' turns\[CuS{{O}_{4}}\]. Solution blue on passing through it. M and B can be:

    A)  \[Al\]&\[N{{H}_{3}}\]                     

    B)  Li &\[N{{H}_{3}}\]

    C)  Na &\[N{{H}_{3}}\]           

    D)  Mg &\[N{{H}_{3}}\]

    Correct Answer: B

    Solution :

     Since the gas B turns \[CuS{{O}_{4}}\]solution blue, it can be \[N{{H}_{3}}.\] Since formula of the given compound A is \[{{\text{M}}_{\text{3}}}\text{N,}\] A is either lithium or sodium nitride. Of the two, \[\text{L}{{\text{i}}_{\text{3}}}\text{N}\] is most likely since it is a stable, very high melting compound.


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