A) \[HgC{{l}_{2}}\]and \[H{{g}_{2}}C{{l}_{2}}\]
B) \[H{{g}_{2}}C{{l}_{2}}\]and\[HgC{{l}_{2}}\]
C) \[HgC{{l}_{2}}\]and \[ZnC{{l}_{2}}\]
D) \[ZnC{{l}_{2}}\]and\[HgC{{l}_{2}}\]
Correct Answer: B
Solution :
\[\underset{(A)}{\mathop{H{{g}_{2}}}}\,C{{l}_{2}}+2N{{H}_{4}}OH\xrightarrow[{}]{{}}\] \[[{{H}_{2}}N-\underset{(Black)}{\mathop{Hg-Cl}}\,+Hg]\downarrow +N{{H}_{4}}Cl+2{{H}_{2}}O\] \[Hg\underset{(White)}{\mathop{(N{{H}_{2}})}}\,Cl+N{{H}_{4}}Cl+{{H}_{2}}O\] \[\underset{(B)}{\mathop{HgC{{l}_{2}}}}\,+2N{{H}_{4}}OH\xrightarrow[{}]{{}}\] \[HgC{{l}_{2}}+2KI\xrightarrow[{}]{{}}\underset{(\operatorname{Re}d)}{\mathop{Hg{{I}_{2}}\downarrow }}\,+2KCl\] \[Hg{{I}_{2}}+2KI(excess)\xrightarrow[{}]{{}}{{K}_{2}}(Hg{{I}_{4}})\]
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