JEE Main & Advanced Sample Paper JEE Main Sample Paper-3

  • question_answer
    The number of 71 electrons present in 6.4 g of calcium carbide is - (\[{{N}_{A}}=\]Avagadro's number)

    A)  \[4{{N}_{A}}\]                

    B)  \[0.4{{N}_{A}}\]

    C)  \[0.1{{N}_{A}}\]                              

    D)  \[0.2{{N}_{A}}\]

    Correct Answer: B

    Solution :

     


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