A) 4
B) 5
C) 9
D) 11
Correct Answer: A
Solution :
\[pOH=p{{K}_{b}}+\log \frac{\text{ }\!\![\!\!\text{ salt }\!\!]\!\!\text{ }}{\text{ }\!\![\!\!\text{ base }\!\!]\!\!\text{ }}\] \[=-\log {{10}^{-10}}+\log 1=10;pH=14-10=4\]You need to login to perform this action.
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