A) 3276 J
B) 1638 J
C) 819 J
D) 409.5 J
Correct Answer: B
Solution :
\[{{T}_{1}}=273K,{{T}_{2}}=2\times 273\] (on doubling Pat const V,T doubles) \[\Delta T=\text{273K,Q}\,\text{=}\,\text{n}{{\text{C}}_{\text{v}}}\text{dt,ms}=3\text{J/g/K,n}{{\text{C}}_{\text{v}}}=3\] \[\Rightarrow \]\[\frac{1}{4}\times {{C}_{V}}=3\] \[\therefore \]\[{{C}_{V}}=12\text{J/mol/K,n }\!\!'\!\!\text{ }{{\text{C}}_{\text{v}}}=\frac{1}{2}\times 12=6\] \[Q=n'{{C}_{v}}dt=6\times 273=1638\text{J}\]You need to login to perform this action.
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