A) B will give an isomer of A
B) C will give an isomer of A
C) Neither of them will give isomer of A
D) Both B and C will give isomer of A
Correct Answer: B
Solution :
Entailers of \[{{C}_{4}}{{H}_{10}}O\] are \[\left. {{\text{H}}_{\text{3}}}\text{C}{{\text{H}}_{\text{2}}}\text{C}-\underset{\begin{smallmatrix} \text{ }\!\!|\!\!\text{ } \\ \text{H} \end{smallmatrix}}{\overset{\begin{smallmatrix} \text{OH} \\ \text{ }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{C}}}}\,-\text{C}{{\text{H}}_{\text{3}}} \right|{{\text{H}}_{\text{3}}}\text{C}-\underset{\begin{smallmatrix} \text{ }\!\!|\!\!\text{ } \\ \text{H} \end{smallmatrix}}{\overset{\begin{smallmatrix} \text{HO} \\ \text{ }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{C}}}}\,-\text{C}{{\text{H}}_{2}}\text{C}{{\text{H}}_{\text{3}}}\] \[\text{C}{{\text{H}}_{\text{3}}}\text{C}{{\text{H}}_{\text{2}}}-\underset{\text{A}}{\overset{\begin{smallmatrix} \text{OH} \\ \text{ }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{C}}}}\,\text{H}-\text{C}{{\text{H}}_{\text{3}}}\xrightarrow[{}]{{{H}_{2}}S{{O}_{4}}}\] \[\text{C}{{\text{H}}_{\text{3}}}\underset{\text{Major}\,\text{(B)}}{\mathop{\text{CH}\,\text{=}\,\text{CH}}}\,-\text{C}{{\text{H}}_{\text{3}}}\text{+C}{{\text{H}}_{\text{2}}}\text{=}\underset{\text{Minor}\,\text{(C)}}{\mathop{\text{CHC}{{\text{H}}_{\text{2}}}}}\,\text{C}{{\text{H}}_{\text{3}}}\]
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