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JEE Main & Advanced Sample Paper JEE Main Sample Paper-3

  • question_answer
    A reaction is found to be second order w.r.t. one of the reactants & has rate constant of \[0.5\text{ }mo{{l}^{-1}}\text{ }d{{m}^{3}}\text{ }{{\min }^{-1}}.\]If initial concentration is \[0.2\text{ }mol\text{ }d{{m}^{-3}}\]then \[{{t}_{1/2}}\]of reaction is

    A)  5 min                   

    B)  10 min

    C)  15 min                

    D)  20 min

    Correct Answer: B

    Solution :

     In general \[{{t}_{1/2}}\]of reaction \[\propto \frac{1}{{{({{a}_{0}})}^{n-1}}}\] For a second order reaction, \[{{t}_{1/2}}=\frac{1}{K{{({{a}_{0}})}^{n-1}}}=\frac{1}{K({{a}_{0}})}=\frac{1}{0.5\times 0.2}=10\min \]


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