A) 0.55 m
B) 55 m
C) 5.5 m
D) \[55\times {{10}^{-4}}m\]
Correct Answer: A
Solution :
Time taken in travelling horizontal distance of 200m with constant velocity of 600m/s is equal to 200/600 = 1/3 sec. Vertical distance moved under acceleration due to gravity, with zero initial velocity will be \[S=ut+\frac{1}{2}a{{t}^{2}}=0+\frac{1}{2}\times 10\times {{(1/3)}^{2}}=0.55m\]Hence, the bullet should be aimed 0.55m higher than target.You need to login to perform this action.
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