A) \[h\rho g\]
B) \[h\rho (g-a)\]
C) \[h\rho (g+a)\]
D) \[2h\rho g\left( \frac{g+a}{g-a} \right)\]
Correct Answer: C
Solution :
When a beaker containing a liquid of density \[\text{ }\!\!\rho\!\!\text{ }\] moves up with an acceleration a, it will work as a lift moving upward with acceleration a. The effective acceleration due to gravity in lift = (a + g) \[\therefore \]Pressure of liquid of height h = h \[\text{ }\!\!\rho\!\!\text{ }\] (a + g)
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