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JEE Main & Advanced Sample Paper JEE Main Sample Paper-3

  • question_answer
    A proton, a deutron and an \[\alpha \]particle accelerated through the same potential difference enter a region of uniform magnetic field, moving at right angles to B. What is the ratio of their K.E.?

    A)  1 : 2 : 2                                

    B)  2 : 2 : 1  

    C)  1 : 2 : 1                                

    D)  1 : 1 : 2

    Correct Answer: D

    Solution :

     K..E. gained by charged particle of charge q when accelerated under a pot. diff. V will be \[{{E}_{k}}=qV;\] For a given \[V,E\propto q.\] For proton, deutron and a-particle, the ratio of charges is 1 :1 : 2.


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