JEE Main & Advanced Sample Paper JEE Main Sample Paper-3

  • question_answer
    A simple pendulum with a bob of mass 'm' oscillates from A to C and back to A such that PB is H. If the acceleration due to gravity is 'g' then the velocity of the bob as it passes through B is                 p

    A)  zero                     

    B)  \[2\,\,gH\]

    C)  mgH                     

    D)  \[\sqrt{2\,\,gH}\]

    Correct Answer: D

    Solution :

     At B, the velocity is maximum. Taking vertical downward motion of body from A to B, we have, \[u=0,a=g,s=H\]and v = ? As\[{{v}^{2}}={{u}^{2}}+2\]as; so\[{{v}^{2}}=0+2gH\]or\[v=\sqrt{2gH}\]


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