A) \[a=3,b=-3\]
B) \[a=9,b=3\]
C) \[a=0,b=-6\]
D) \[a=3,b=9\]
Correct Answer: B
Solution :
Both the curves satisfied by the point \[(1,{{y}_{1}})\] So, \[1+a-1=6+b\Rightarrow a-b=6\] ...(1) Also\[\frac{dy}{dx}{{\left| _{\text{curve1}}=\frac{dy}{dx} \right|}_{\text{curve2}}}\]at x = 1 \[{{[3{{x}^{2}}+a]}_{x=1}}={{[12x]}_{x=1}}\Rightarrow a=9\] ?(2) From (1) & (2) \[a=9\]and b = 3.You need to login to perform this action.
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