A) \[\alpha =1,\beta =1\]
B) \[\alpha =2,\beta =-1\]
C) \[\alpha =1,\beta =-2\]
D) \[\alpha =-2,\beta =-1\]
Correct Answer: B
Solution :
(1,1) satisfies \[g(x)=\alpha x+\beta \therefore \alpha +\beta =1\] (2,3) satisfies \[g(x)=\alpha x+\beta \therefore 2\alpha +\beta =3\] Solving the two equation, we get \[\alpha =2,\beta =-1\] It can be checked that other ordered pairs satisfy g(x) = 2x -1
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