A) 2
B) 1
C) 0
D) infinite
Correct Answer: A
Solution :
\[f\{f[fx]\}=f\left[ f\left( \frac{1}{1-x} \right) \right]=f\left( \frac{1}{1-\frac{1}{1-x}} \right)\] \[=f\left( \frac{x-1}{x} \right)\] \[\therefore \]f (x) is not defined for x = 1; \[f\left( \frac{1}{1-x} \right)\]is not defined for x = 0. \[\therefore \]f{f[f(x)]} is discontinuous at x = 0 and 1 i.e., there are two points of discontinuity.You need to login to perform this action.
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