A) \[{{[Zn{{(N{{H}_{3}})}_{4}}]}^{+2}}\]
B) \[Ni{{(CO)}_{4}}\]
C) \[{{[Cd{{(CN)}_{4}}]}^{-2}}\]
D) \[{{[Cu{{(N{{H}_{3}})}_{4}}]}^{+2}}\]
Correct Answer: D
Solution :
\[{{[Zn{{(N{{H}_{3}})}_{4}}]}^{2+}},Ni{{(CO)}_{4}}\And {{[Cd{{(CN)}_{4}}]}^{2-}}\] all form tetrahedral structures where the central atom uses sp3 hybridisation. Whereas \[{{[Cu{{(N{{H}_{3}})}_{4}}]}^{2+}}\] uses dsp2 hybridisation and forms square planar structure. Although Cu should use both tetrahedral (sp3) & square planar (dsp2) hybridisations but the later one is confirmed through X-ray analysis.
You need to login to perform this action.
You will be redirected in
3 sec
