A) 8
B) 12
C) 3
D) 6
Correct Answer: B
Solution :
Total pressure of mixture of gases A,B & C = 10 atm. Partial pressure of A = (No. of moles of Ax 10)/10 or (No. of moles of A x10) / 10 = 3 Hence, no. of moles of A= 3 \[\therefore \]Partial pressure of B = (No. of moles of Bx10) /10 (since partial pressure of B=1 atm) \[\therefore \]No. of moles of B = 1 Now the no. of moles of C = 10 - (3+1) = 6; mole of C weighs = 2 gm. \[\therefore \]6 mole of C will weigh = 2 x 6 = 12You need to login to perform this action.
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