2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-40

  • question_answer
    A 55 gm tennis ball strikes the ground and rebounds back. If its velocities are 5 m/s and 4 m/s before and after the collision respectively then the impulse imparted will be

    A) - 0.495 Ns                   

    B) 0.495 Ns

    C) 495 Ns                        

    D) -495Ns

    Correct Answer: A

    Solution :

    [a] Impulse = Change in momentum = Final momentum - Initial momentum =[0.055 x (- 4)] -[0.055x5] =-0.055 x 9 = - 0.495 N/sec


You need to login to perform this action.
You will be redirected in 3 sec spinner