A) phenyl hydrazine
B) semicarbazide
C) biuret
D) acetylurea
Correct Answer: B
Solution :
\[N{{H}_{2}}CON{{H}_{2}}+N{{H}_{2}}-N{{H}_{2}}\xrightarrow[{}]{{}}\underset{(Semicarbazide)}{\mathop{N{{H}_{2}}NHCON{{H}_{2}}}}\,+N{{H}_{3}}\]You need to login to perform this action.
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