A) 900 cal.
B) 625 cal.
C) 750 cal.
D) 1000 cal.
Correct Answer: A
Solution :
[a] We know that \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{300-250}{300}=\frac{50}{300}=\frac{1}{6}\] or\[\eta =1-\frac{{{Q}_{2}}}{{{Q}_{1}}}\Rightarrow \frac{1}{6}=\frac{{{Q}_{1}}-750}{{{Q}_{1}}}\] \[{{Q}_{1}}=6{{Q}_{1}}-4500\Rightarrow -5{{Q}_{1}}-4500\Rightarrow {{Q}_{1}}=900Cal\]
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