A) 0.65 mm
B) 1.63 mm
C) 3.25 mm
D) 4.88 mm
Correct Answer: B
Solution :
[b] \[\beta =\frac{\lambda D}{2d}=\frac{6.5\times {{10}^{-7}}}{{{10}^{-3}}}\times 1=0.65\times {{10}^{-3}}=0.65mm\] The distance between fifth bright fringe from third dark fringe \[=2.5\beta =2.5\times .65=1.63mm\].You need to login to perform this action.
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