question_answer

\[RCON{{H}_{2}}+4NaOH+B{{r}_{2}}\to RN{{H}_{2}}+2NaBr\]\[+N{{a}_{2}}C{{O}_{3}}+2{{H}_{2}}O\] Reaction is said

A)  Hofmann-bromamide reaction

B)  Schmidt reaction

C)  Curtius reaction

D)  Beckmann reaction.

Correct Answer: A

Solution :

\[R-\overset{\begin{smallmatrix}  O \\  || \end{smallmatrix}}{\mathop{C}}\,-N{{H}_{2}}+B{{r}_{2}}\to R-\overset{\begin{smallmatrix}  O \\  || \end{smallmatrix}}{\mathop{C}}\,-\overset{..}{\mathop{N}}\,HBr\xrightarrow[-{{H}^{+}}]{{}}\] This reaction is called Hofmann-bromamide reaction.