A) 0.8 A, 0.4 A, 0.4 A
B) 0.5 A, 0.25 A, 0.25 A
C) (8/13) A, (4/13) A, (4/13) A
D) None of the above
Correct Answer: B
Solution :
Write KVL for CDFE \[{{I}_{2}}(2+2+1+1)-4-{{I}_{3}}(2+2+1+1)+4=0\] \[\Rightarrow \] \[6{{I}_{2}}=6{{I}_{3}}\] \[\Rightarrow \] \[{{I}_{2}}={{I}_{3}}\] ?(i) And \[{{I}_{2}}+{{I}_{3}}+{{I}_{1}}\] ?(ii) Apply KVL for EFAB \[{{E}_{3}}(2+2+1+1)-4+{{I}_{1}}(5)=0\] ?(iii) After solving the Eqs. (i), (ii) and (iii), we get \[{{I}_{1}}=0.5A,{{I}_{2}}=0.25A,{{I}_{3}}=0.25A\]You need to login to perform this action.
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