A) 0.1%
B) 1%
C) 0.2%
D) 0.8%
Correct Answer: C
Solution :
\[T=2\pi \sqrt{\frac{l}{g}}\] \[{{T}^{2}}=4{{\pi }^{2}}\frac{l}{g}\]\[\Rightarrow \]\[g=\frac{4{{\pi }^{2}}l}{{{T}^{2}}}\] Here percentage error in \[l=\frac{1\,mm}{100\,cm}\times 100=\frac{0.1}{100}\times 100=0.1%\] and % error in \[T=\frac{0.1}{2\times 100}\times 100=0.05%\] \[\therefore \] % error in g = % error in I + 2 (% error in T) = 0.1+ 2 x 0.05 = 0.2%You need to login to perform this action.
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