A) Reaction follows \[{{E}_{1}}\] path
B) \[~Rate=k{{\left[ Bromide \right]}^{1}}\left[ KOH \right]{}^\circ \]
C) Reaction is stereo specific
D) Reaction is stereo selective
Correct Answer: C
Solution :
\[3{}^\circ \] halide in alcoholic KOH prefers \[{{\text{E}}_{\text{1}}}\] path
II (more stable) product is the major product and the reaction is stereo selective not stereo specific
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