A) ethenyl nitrile
B) prop-2-en-l-cyanide
C) prop-2-en-l-nitrile
D) eth-1-en-l-nitrile
Correct Answer: C
Solution :
\[\underset{3}{\mathop{C{{H}_{2}}}}\,=\underset{2}{\mathop{CH}}\,-\underset{1}{\mathop{C}}\,\equiv N\]Prop- 2-ene-1-nitrile
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