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JEE Main & Advanced Sample Paper JEE Main Sample Paper-41

  • question_answer
    The vapour pressure of pure liquid solvent A is atm. When a nonvolatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm. What is the mole fraction of component B in the solution?

    A)  0.75                           

    B)  0.25

    C)  0.40                           

    D)  0.60

    Correct Answer: B

    Solution :

    \[p={{X}_{A}}{{p}^{o}}{{X}_{A}}=\frac{p}{{{p}^{o}}}=\frac{0.60\,atm}{0.80}=0.75\]\[{{X}_{B}}=1-0.75=0.25\]


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