A) Isohypophosphoric acid
B) Diphosphorus acid
C) Diphosphoric acid
D) Hypophosphoric acid
Correct Answer: D
Solution :
Hypophosphoric acid \[({{H}_{4}}{{P}_{2}}{{O}_{6}})\] Isohypophosphoric acid \[({{H}_{4}}{{P}_{2}}{{O}_{6}})\] \[\text{H}-\underset{\begin{smallmatrix} \text{ }\!\!|\!\!\text{ } \\ \text{OH} \end{smallmatrix}}{\overset{\begin{smallmatrix} \text{O} \\ \text{ }\!\!|\!\!\text{ }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{P}}}}\,-\text{O}-\underset{\begin{smallmatrix} \text{ }\!\!|\!\!\text{ } \\ \text{OH} \end{smallmatrix}}{\overset{\begin{smallmatrix} \text{O} \\ \text{ }\!\!|\!\!\text{ }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{P}}}}\,-\text{OH}\] Diphosphorus acid (Pyrophosphorus acid, \[{{H}_{4}}{{P}_{2}}{{O}_{5}}\]) \[\text{H}-\underset{\begin{smallmatrix} \text{ }\!\!|\!\!\text{ } \\ \text{OH} \end{smallmatrix}}{\overset{\begin{smallmatrix} \text{O} \\ \text{ }\!\!|\!\!\text{ }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{P}}}}\,-\text{O}-\underset{\begin{smallmatrix} \text{ }\!\!|\!\!\text{ } \\ \text{OH} \end{smallmatrix}}{\overset{\begin{smallmatrix} \text{O} \\ \text{ }\!\!|\!\!\text{ }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{P}}}}\,-\text{H}\] Diphosphoric acid (Pyrophosphoric acid, \[{{H}_{4}}{{P}_{2}}{{O}_{5}}\])You need to login to perform this action.
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