A) an obtuse angled triangle
B) an acute angled triangle
C) a right angled triangle
D) None of the above
Correct Answer: D
Solution :
The area of triangle formed by the vertices. \[\left( 0,\frac{8}{3} \right),\] (1, 3) and (82, 30) \[=\frac{1}{2}\left| \begin{matrix} 0 & \frac{8}{3} & 1 \\ 1 & 3 & 1 \\ 82 & 30 & 1 \\ \end{matrix} \right|\] \[=\frac{1}{2}\left[ -\frac{8}{3}(1-82)+1(30-246) \right]\] \[=\frac{1}{2}[216-216]=0\] Thus, the points are collinear.
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