Direction: Question based on the following paragraph. |
Two rods 1 and 2 are released from rest as shown in figure. |
Given:\[{{l}_{1}}=4l,{{m}_{1}}=2m,{{l}_{2}}=2l\]and\[{{m}_{2}}=m.\]There is no friction between the two rods. If \[\alpha \]be the angular acceleration of rod 1 just after the rods are released. Then |
A) \[\left( \frac{32-12\sqrt{3}}{3\sqrt{3}} \right)ml\alpha \]
B) \[\left( \frac{16-2\sqrt{3}}{\sqrt{3}} \right)ml\alpha \]
C) \[(14+2\sqrt{3})ml\alpha \]
D) \[\sqrt{3}ml\alpha \]
Correct Answer: A
Solution :
\[N-F=(2m){{a}_{c}}=(2m)(2l)\alpha =ml\alpha \] \[\therefore \]\[F=N-4ml\alpha =\left( \frac{32-12\sqrt{3}}{3\sqrt{3}} \right)=ml\alpha \]You need to login to perform this action.
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