A) 1/2
B) -1/2
C) 1
D) - 1
Correct Answer: B
Solution :
\[KE=\frac{m{{v}^{2}}}{2},PE=\frac{-Z{{e}^{2}}}{r}\] But electrostatic force of attraction \[\left( \frac{Z{{e}^{2}}}{{{r}^{2}}} \right)=\]centripetal force\[\left( \frac{m{{v}^{2}}}{r} \right)\]or\[\frac{Z{{e}^{2}}}{r}=m{{v}^{2}}\] Therefore,\[PE=-m{{v}^{2}}\]\[\frac{KE}{PE}=\frac{-1}{2}\]You need to login to perform this action.
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