JEE Main & Advanced Sample Paper JEE Main Sample Paper-42

  • question_answer
    Chords of an ellipse are drawn through the positive end of the minor axis. Then, their mid point lies on

    A)  a circle                       

    B)  a parabola

    C)  an ellipse       

    D)  a hyperbola

    Correct Answer: C

    Solution :

    Let (h, k) be the mid point of a chord passing through the positive end of the minor axis of the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1.\]Then, the equation of the chord is                           \[\frac{hx}{{{a}^{2}}}+\frac{ky}{{{b}^{2}}}-1=\frac{{{h}^{2}}}{{{a}^{2}}}+\frac{{{k}^{2}}}{{{b}^{2}}}-1\](using T = S?) \[\Rightarrow \]\[\frac{hx}{{{a}^{2}}}+\frac{ky}{{{b}^{2}}}=\frac{{{h}^{2}}}{{{a}^{2}}}+\frac{{{k}^{2}}}{{{b}^{2}}}\] This passes through (0, b). \[\therefore \]\[\frac{k}{b}=\frac{{{h}^{2}}}{{{a}^{2}}}+\frac{{{k}^{2}}}{{{b}^{2}}}\]. Hence, the locus of (h, k) is \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=\frac{y}{b},\] which represents an ellipse.


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