A) \[^{6}{{C}_{3}}{{\times }^{3}}{{C}_{2}}\]
B) \[^{4}{{P}_{2}}{{\times }^{4}}{{P}_{3}}\]
C) \[^{4}{{C}_{2}}{{+}^{4}}{{P}_{3}}\]
D) None of these
Correct Answer: D
Solution :
Since, first the 2 women select the chairs amongst 1 to 4. \[\therefore \]Number of ways \[{{=}^{4}}{{P}_{2}}\] Now, from the remaining 6 chairs three men could be arranged in \[^{6}{{P}_{3}}\] ways. \[\therefore \]Total number of arrangements \[{{=}^{4}}{{P}_{2}}{{\times }^{6}}{{P}_{3}}.\]
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