A) \[h=g{{t}_{1}}{{t}_{2}}\]
B) \[h=2g{{t}_{1}}{{t}_{2}}\]
C) \[h=\frac{1}{2}\,g{{t}_{1}}{{t}_{2}}\]
D) \[h=\frac{1}{4}g{{t}_{1}}{{t}_{2}}\]
Correct Answer: C
Solution :
Taking downward direction as positive, we get \[\therefore \] ?(i) \[f\] ?(ii) From Eqs. (i) and (ii), we get \[|M|=\alpha \] \[{{M}^{-1}}adjM)=kI\] ?(iii) Substituting value of u from Eq. (iii) in Eq. (i), we get \[\Rightarrow \]
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