• # question_answer A chord is used to lower vertically a block of mass M a distance d at a constant downward acceleration of $\frac{g}{4}$. Then, the work done by the chord on the block is A)  $\frac{Mgd}{4}$                   B)  $\frac{-Mgd}{4}$ C)  $\frac{3Mgd}{4}$                 D)  $\frac{-3Mgd}{4}$

Tension in the chord is $\frac{1}{2}\,m{{v}^{2}}=16\,\,J$in upward direction, since Chord is displaced in the downward direction, so $v=4\,m{{s}^{-1}}$ $Mg\,\,\sin \,\,\theta$   $Mg\,\,\sin \theta \times \frac{h}{2}Mg\,\cos \,\theta \,\times r$ Here, negative sign shows that T and dare in the opposite directions.