• question_answer A tank is filled with water of density $1\text{ }g/c{{m}^{3}}$ and oil of density $0.9\text{ }g/c{{m}^{3}}$ . The height of water layer is 100 cm and of the oil layer is 400 cm. lf $g=980\text{ }cm/{{s}^{2}}$ , then the velocity of efflux from an opening in the bottom of the tank is A)  $\sqrt{900\times 980}\,\,cm/s$          B)  $\sqrt{100\times 980}\,\,cm/s$ C)  $\sqrt{920\times 980}\,\,cm/s$          D)  $\sqrt{950\times 980}\,\,cm/s$

Let, $\Rightarrow$ and $v'\frac{v}{\sqrt{2}}$ be the densities of water and oil, then the pressure at the bottom of the tank $={{h}_{w}}{{d}_{w}}g+{{h}_{o}}{{d}_{o}}g$ Let, this pressure be equivalent to pressure due to water of height h. Then, $E=\frac{1}{2}mv{{'}^{2}}+\frac{1}{2}mv{{'}^{2}}+\frac{1}{2}(2m){{v}^{2}}$ $=mv{{'}^{2}}+m{{v}^{2}}$   $\Rightarrow$ $m{{\left( \frac{v}{\sqrt{2}} \right)}^{2}}+m{{v}^{2}}=\frac{3}{2}m{{v}^{2}}$ ${{T}_{1}}-{{T}_{2}}=12a$ According to Tori celli's theorem, ${{T}_{2}}=3a$ ${{T}_{2}}$
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