• # question_answer A open manometer attached to a flask containing ammonia gas have no difference in mercury level initially as shown in fig. After sparking into the flask, ammonia is partially dissociated as  $2N{{H}_{3}}\,(g)\,\xrightarrow{\,}\,{{N}_{2}}\,(g)\,+3{{H}_{2}}\,(g)$. Now it have difference of 18cm in mercury level into columns, what is partial pressure of ${{H}_{2}}(g)$ at equilibrium?                                                          A)  9 cm Hg                      B)  18 cm Hg C)  27 cm Hg                    D)  None of these

Solution :

$\therefore$ ${{x}_{2}}=\frac{{{m}_{1}}}{{{m}_{2}}}{{x}_{1}}$ ${{m}_{1}}=\frac{M}{4},\,{{x}_{1}}=\frac{R}{2}$ ${{m}_{2}}=\frac{3M}{4}$           ${{x}_{2}}=-\frac{M/4}{3M/4}\cdot \frac{R}{2}=\frac{-R}{6}$ $\frac{R}{6}$            ${{d}_{w}}$ ${{d}_{o}}$ of Hg

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