A) \[\frac{\omega BA}{\pi }\]
B) \[\frac{\omega BA}{2\pi }\]
C) \[\frac{\omega BA}{4\pi }\]
D) \[\frac{2\omega BA}{\pi }\]
Correct Answer: D
Solution :
\[\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{15a}{3a}=\frac{5}{1}\] Flux passing through the area of the coil when it is far to magnetic field \[\Rightarrow \] and \[{{T}_{1}}:{{T}_{2}}=5:1\] Flux passing through the area of the coil when it is \[T=M\,\left( g-\frac{g}{4} \right)=\frac{3Mg}{4}\] to the magnetic field \[W=\mathbf{T}\cdot \mathbf{d}\Rightarrow \,W=Td\] \[\Rightarrow \] \[W=-Td=-\frac{3Mgd}{4}\] But \[\Sigma mvr=\,({{l}_{system}})\omega \] \[\Rightarrow \] \[mv\frac{l}{2}=\frac{(2m)\,{{(2l)}^{2}}}{12}\omega =\frac{2m(4{{l}^{2}})}{12}\omega \]You need to login to perform this action.
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