• # question_answer A charge $Q$ is divided into two parts q and q' and separated by a distance R. The force of repulsion between them will be maximum, when A)  $q=\frac{Q}{4}$                 B)  $q=\frac{Q}{2}$ C)  $q=Q$                      D)  None of these

Correct Answer: B

Solution :

As total charge $Eq$ ${{T}_{1}}=15a$    $\therefore$ $\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{15a}{3a}=\frac{5}{1}$ Force between the charges q and q' $\Rightarrow$ For maximum value of F ${{T}_{1}}:{{T}_{2}}=5:1$ or $T=M\,\left( g-\frac{g}{4} \right)=\frac{3Mg}{4}$ $W=\mathbf{T}\cdot \mathbf{d}\Rightarrow \,W=Td$       $\Rightarrow$or         $W=-Td=-\frac{3Mgd}{4}$

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