JEE Main & Advanced Sample Paper JEE Main Sample Paper-43

  • question_answer
    A reaction \[A\to B\] involves the following mechanism
    Step 1 \[2A\xrightarrow{{{k}_{1}}}C\] (fast)
    Stem 2 \[C\xrightarrow{{{k}_{2}}}D\] (slow)
    Step3 \[3D\,\xrightarrow{{{k}_{3}}}B\] (fast)
    The rate law of the reaction may be given as

    A)  rate\[={{k}_{1}}{{[A]}^{2}}\]                

    B)  rate

    C)  rate\[={{k}_{2}}[C]\,\,[D]\]

    D)  rate\[={{k}_{1}}{{k}_{2}}{{k}_{3}}\,[C]\,\,[D]\]

    Correct Answer: B

    Solution :

           Rate \[u=v+at\] Now,    \[0=v-at\] \[\therefore \]    \[-a=\frac{0-v}{t}=-\frac{v}{t}\] \[f=\mu R=\mu mg\]   Rate\[a=\mu g\]

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