• # question_answer Identify the correct statement. A)  ${{P}_{4}}{{O}_{11}}$contains peroxide linkages B)  ${{P}_{4}}{{O}_{10}}$contains$p\pi -d\pi$ back bonding C)  In ${{P}_{4}}{{O}_{10}}$ each P atom is bonded to three oxygen atoms D)  ${{P}_{4}}{{O}_{10}}$hydrolyze in water forming phosphorous acid

The structure of $\therefore$ is as Therefore each P atom is bonded with four oxygen atom. $t=\frac{v}{a}=\frac{v}{g\mu }$ back bonding is found in the $\eta =\frac{{{P}_{0}}}{{{P}_{i}}}$ of $\therefore$. It forms orthophosphoric acid when hydrolyzed $\frac{1}{2}\,m{{v}^{2}}=16\,\,J$