JEE Main & Advanced Sample Paper JEE Main Sample Paper-43

  • question_answer
    The following graph is obtained when the fraction of molecules is plotted against velocity. The profile curve will be same for the gases.
    (I) Oxygen gas at T temperature
    (II) Hydrogen gas at 2T temperature
    (III) Helium gas at 2T temperature
    (IV) Sulphur dioxide gas at 2T temperature

    A)  I and II                       

    B)  II and III          

    C)  I and IV                      

    D)  III and IV

    Correct Answer: C

    Solution :

     Graph having same M/T value will have same profile curve \[v=4\,m{{s}^{-1}}\]           \[Mg\,\,\sin \,\,\theta \] \[Mg\,\,\sin \theta \times \frac{h}{2}Mg\,\cos \,\theta \,\times r\]\[\tan \theta =\frac{r}{h/2}\] \[\theta ={{45}^{o}},\]        \[r=\frac{h}{2}\] Hence, they have the same profile curve.

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