A) increases
B) decreases
C) remains same
D) Non-e of these
Correct Answer: A
Solution :
During electrolysis of concentrated aqueous solution of \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\left[ \frac{Q}{R} \right]+\frac{1}{4\pi {{\varepsilon }_{0}}}\left[ \frac{q}{r} \right]\], chlorine gas is released at anode and \[=\frac{1}{{{\varepsilon }_{0}}}\left[ \frac{Q}{4\pi {{R}^{2}}}\times R+\frac{q}{4\pi {{r}^{2}}}\times r \right]\] gas is liberated at cathode leaving \[\frac{Q}{4\pi {{R}^{2}}}=\frac{q}{4\pi {{r}^{2}}}=\sigma \] and \[\therefore \] ions in the solution, i.e., \[V=\frac{1}{{{\varepsilon }_{0}}}\,[\sigma R+\sigma r]=\frac{\sigma }{{{\varepsilon }_{0}}}[R+r]\] concentration increases. Therefore, pH increases.
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