A) \[{{x}^{2}}+{{y}^{2}}+x+2y+4=0\]
B) \[{{x}^{2}}+{{y}^{2}}+x-2y+4=0\]
C) \[{{x}^{2}}+{{y}^{2}}-x-2y+4=0\]
D) \[{{x}^{2}}+{{y}^{2}}-x+2y+4=0\]
Correct Answer: C
Solution :
Given, \[\Rightarrow \] \[[\because |adj\,(adj\,A)|=\,A{{|}^{{{(n-1)}^{2}}}}]\] and \[=100\,\left( \frac{\Delta \phi }{\Delta t} \right)\]You need to login to perform this action.
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